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using Popup on outer table of MULTI4 [message #1142]

Thu, 25 October 2007 13:13

alrobertson
Messages: 9
Registered: October 2007
Location: Vancouver

Junior Member

When I use a popup for a field in the outer table of a MULTI4,
the outer table's popcall() function does not get called but the inner tables popupcall() function gets called instead.

I made a small change to childForm() to get me by. I added
$found_x = true; to the conditional where _x$ is being stripped off. Then added this code after the 'popup|filepicker' has been determined:

if (($pattern_id == 'MULTI4') AND ($found_x)) {
reset($object_array);
$objectname = key($object_array);
$dbobject = $object_array[$objectname];
}

I'm sure you will have a better way, but I thought I should let you know about the issue.

Thanks

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Re: using Popup on outer table of MULTI4 [message #1143 is a reply to message #1142]

Thu, 25 October 2007 18:13

AJM
Messages: 2369
Registered: April 2006
Location: Surrey, UK

Senior Member

Here is the fix which I have just tested. Within function childForm() in file include.session.inc change

    if (is_array($value)) {
        $offset = key($value);
    } else {
        $offset = 1;
    } // if

    if (is_array($value)) {
        $offset = key($value);
    } else {
        $offset = 1;
        if (count($object_array) > 1) {
            // set to previous entry in array
            $null       = prev($object_array);
            $objectname = key($object_array);
            $dbobject   = $object_array[$objectname];
        } // if
    } // if

Let me know if this works for you and I shall include it in the next release.

Tony Marston
http://www.tonymarston.net
http://www.radicore.org

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